Die armours?

[Gladius]

For a unit like the Hero, with an armour amount as 2d6, when do you roll this amount? At the beginning of the game, where it is constant throughout the battle, or every time his armor is at stake?

I've normally used the former, but I'm not sure what it "officially" is.

[Blitzen]

Every time his armour is at stake. This would be the same for minifigs, but since they are so common it is reduced to 4.

EDIT: I mean the roll is reduced form 1d6 to 4.

[Moronstudios]

You roll every time he/she takes damage.

[Olothontor]

A fact that has saved my Tekmage many a time. That and it would really suck if you rolled two ones at the beginning of the game.

[Tesla Coyle]

When my friends and I play we use a variant rule we call "Taking 2/3." We came up with it from a D&D 3.5 variant rule from Unearthed Arcana. In D&D you get a base armor class of 10 which is the average roll on a d20. The variant rule allows you to rolled your armor class every time you are attacked.

Essentially we instituted it backwards so that instead of rolling you can take the "average" roll. Since the standard minifig uses a 4 from a roll of 1d6, which is 2/3, we allow a player to take 2/3 of his maximum possible armor roll.

[Rayhawk]

I actually calculated out all the die roll probabilities, including the critical-success possibility of bonus dice earning bonus dice ad infinitum; in all cases they round to half the number of sides, plus one.

avg die roll (once) = (d+1)/2
avg die roll (exploding) = (d+d^2)/(2d-2)
avg d6 roll (exploding) = (6+36)/(12-2) = (42/10) = 4.2
avg die roll (exploding d6es) = (d+1)/2 + 4.2/d

avg d4 (no bonus dice): (4+1)/2 = 2.5 ~ 3
avg d6: (6+1)/2 + 4.2/6 = 3.5 + .7 = 4.2 ~ 4
avg d8: (8+1)/2 + 4.2/8 = 4.5 + .525 = 5.025 ~ 5
avg d10: (10+1)/2 + 4.2/10 = 5.5 + .42 = 5.92 ~ 6
avg d12: (12+1)/2 + 4.2/12 = 6.5 + .35 = 6.85 ~ 7
avg d20: (20+1)/2 + 4.2/20 = 10.5 + .21 = 10.71 ~ 11

So there you go, for every die you can use the value (d/2)+1.

[Tesla Coyle]

Thanks. I'll try it out at my next battle.